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★声明:本文仅代表个人观点,笔者学识有限,资料整理过程中难免存在疏漏谬误,请不吝指正。 高对称性导致的无序如何处理和理解1 案例来源:CCDC [1]: 2477580, 2477582. Org. Chem. Front. 2026, 13, 13–24. DOI [2]: 10.1039/d5qo01187f. 案例结构如图1所示(由ChemBioDraw [3]绘制)。 ▲图1 案例结构 两个结构均为单斜晶系第15号空间群C2/c,如图2–3所示(由Olex2 [4]呈现),其不对称单元(ASU, asymmetric unit)为半个结构(参阅推文“不对称单元中包含的分子数目案例”)。 ▲图2 CCDC 2477580不对称单元结构 ▲图3 CCDC 2477582不对称单元结构 分子结构处于2次轴(2-fold axis)上,如图4所示(由Mercury[5]呈现)(参阅视频“Mercury基操-查看对称元素:https://www.bilibili.com/video/BV1U44y1U7ZF”)。 ▲图4 对称元素查看(CCDC 2477582) 该无序处理很简单,将该处的两个Q峰分别定为硫和氧(或硫和氮),然后用SHELXL [6]指令PART(参阅推文“SHELXL指令之PART”)进行分组,再将两个组分的占有率固定为0.5(10.50000)即可,如图5–6所示。 ▲图5 CCDC 2477582无序处理 ▲图6 CCDC 2477580无序处理 无序处理很简单,只是理解和作图上需要转个弯。由于分子处于2次轴上,不对称单元中只有一半结构,硫和氧(或硫和氮)以SHELXL指令PART做分组进行了无序处理,那么对称操作得到的完整分子,左右两侧硫属于相同的PART分组,氧(或氮)属于相同的PART分组,这时如果用“showp 0 1”(展示PART 0和PART 1)和“showp0 2”(展示PART 0和PART 2)来查看两个无序组分,则会得到表观上错误的结构,如图7–9所示。 ▲图7 无序组分PART 1结构(包含PART 0) ▲图8 CCDC 2477582无序组分PART2结构(包含PART 0) ▲图9 CCDC 2477580无序组分PART2结构(包含PART 0) 显然,按照上述理解和作图是错误的,正确理解如图10所示(以CCDC 2477582结构为例,CCDC 2477580结构同理)。 ▲图10 无序处理正确理解 正确的作图方法是,对称操作得到完整结构后,手动删除不要的原子,保留所需原子即可,如图11–12所示。 ▲图11 对称操作得到完整结构后选择想要删除的原子(红色箭头)然后按delete键删除 ▲图12 得到正确表达的结构后输出图片即可 对于这样的无序结构,笔者发现CCDC官网的Chemical diagram可以展示正确结构(可能是论文已发表,CCDC工作人员调整了Chemical diagram,也可能是系统的确能够识别并展示正确结构),如图13–14所示。 ▲图13 CCDC中CCDC 2477582结构 ▲图14 CCDC中CCDC 2477580结构 相关视频: 单晶结构解析练习778(无序处理):https://www.bilibili.com/video/BV1opTV6JEGp 数据下载: 提取码: qpp1 参考文献 [1] (a)Allen, F. 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