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[单晶结构] 晶体结构分子式非整数文献案例3

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声明:本文仅代表个人观点,笔者学识有限,资料整理过程中难免存在疏漏谬误,请不吝指正。
晶体结构分子式非整数文献案例3
案例来源:CCDC [1]: 2203584. Chem2023, 9, 2573–2584. DOI [2]: 10.1016/j.chempr.2023.05.005.
其反应如1所示(由ChemBioDraw [3]绘制),利用MsFluid*-SbCCDC: 2203582)与九羰基二铁(Fe2(CO)9, nonacarbonyldiiron, CAS: 15321-51-4)以正己烷[4]C6H14,n-hexane, CAS: 110-54-3, CCDC: 103189)作溶剂于室温下反应12小时合成目标产物MsFluid*-SbFe(CO)4
1 案例结构合成反应式
Olex2 [5]打开CIF[6]文件2203584.cif,如2所示,查看SbFe(CO)4Br原子信息,可知SbFe(CO)4Br以第二个自由变量(21.00000-21.00000)做二组分无序,占有率之和为1.00000,占有率精修为0.91681,即SbFe(CO)40.91681Br(1 – 0.91681) = 0.08319
2 无序情况
该无序代表的含义是,这个晶体结构为MsFluid*-SbFe(CO)4MsFluid*-Br的混合物,二者比例为0.91681:0.08319,其中溴的来源很可能是通过MsFluid*-SbBr2所合成的MsFluid*-Sb并不纯,导致其与九羰基二铁反应时,生成了部分MsFluid*-Br,其成分和比例如3所示,因此其分子式为0.91681 × (C76H89FeO4Sb) + 0.08319 × (C72H89Br) = C75.66724H89Br0.08319Fe0.91681O3.66724Sb0.91681,保留三位小数即为C75.667H89Br0.083Fe0.917O3.667Sb0.917,与CIF_chemical_formula_moiety(参阅推文“CIF核心词典-CHEMICAL_FORMULA”)一致,保留两位小数即为C75.67H89Br0.09Fe0.91O3.67Sb0.91,与CIF_chemical_formula_sum(参阅推文“CIF核心词典-CHEMICAL_FORMULA”)一致,如4所示,其两个结构如5–6所示。
3 CCDC 2203584结构成分
4 CIF中的分子式
5 MsFluid*-SbFe(CO)4结构
6 MsFluid*-Br结构
视频讲解请参阅:
晶体结构分子式非整数文献案例3https://www.bilibili.com/video/BV1KaLm6DEzn
如需论文PDF和晶体数据CIF文件,请从以下链接下载:
提取码: 3rxm
参考文献
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