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[单晶结构] 文献晶体数据改进示例26(THF占有率)

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发表于 2025-6-21 07:20:28 | 查看全部 |阅读模式
文献晶体数据改进示例26(THF占有率)
案例来源:CCDC[1]: 2172922. Chem. Eur. J. 2022, 28, e202201897. DOI[2]: 10.1002/chem.202201897.
案例结构为(四氢呋喃)双吲哚钙[(THF)4Ca(Ind)2],如1所示(由ChemBioDraw[3]绘制)。
1[(THF)4Ca(Ind)2]结构
CCDC下载其CIF[4]文件(2172922.cif)(参与推文“通过CCDC号下载CIF文件”“通过DOI号下载CIF文件”或视频“CCDC-Access Structures-根据CCDC号查找CIF文件:https://www.bilibili.com/video/BV1ZM4y1f7BJ”“CCDC-Access Structures-根据DOI查找CIF文件:https://www.bilibili.com/video/BV1Lb41197UH”)用Olex2[5]提取并打开CIF中嵌入的reshkl文件(参与推文“提取CIF中的hkl和res文件”或视频“Olex2视频教程——从合并CIF文件中提取hkl文件进行精修:https://www.bilibili.com/video/BV1sb411W7MP”),在Work选项卡下Toolbox WorkLabels下拉菜单中选择Crystallographic Occupancy,如2所示,其溶剂四氢呋喃(THF, , tetrahydrofuran, CAS: 109-99-9)的占有率为0.5,即不对称单元ASUasymmetric unit)中含有0.5THF,主体结构[(THF)4Ca(Ind)2]1个,故而整体结构为[(THF)4Ca(Ind)2]·0.5THF,这与CIF_chemical_formula_moiety(参阅推文“CIF核心词典-CHEMICAL_FORMULA”)条目值'2(C32 H44 Ca N2 O4), C4 H8 O'一致(结构式和分子式本质上是片段或原子数量比例)。
2CCDC 2172922不对称单元结构
Olex2中按下Ctrl+M查看差值电子密度图,如3所示,溶剂THF明显有绿色电子云密度,这表明THF的数量显然大于0.5个。
3THF处差值电子密度图
可以对该THF的占有率使用自由变量进行整体统一自由精修,具体操作如下:选中整个THF,然后输入指令“part 1 41”(因为[(THF)4Ca(Ind)2]中配位的THF的无序已经占用了第2个和第3个自由变量,因此这里使用第4个自由变量,置于分组序号则随便,此处采用1),如4所示。
4设置THF占有率整体统一自由精修
精修后,该THF的占有率为0.98589(接近1),且THF处差值电子密度图变得十分干净,如图5所示,R18.61%降为6.53%wR231.68%降为20.77%,很显然,单从晶体数据来看,该THF定为0.5个是不合理的。
5THF占有率整体统一自由精修结果
把溶剂THF占有率定为1,并对结构中的一些无序进行处理,用SHELXL[6]指令OMIT(参阅推文“SHELXL指令之OMIT”)删除一些离群点(参阅推文“CheckCIF-B级警报PLAT934(如何删除衍射点)”或视频“CheckCIF-B级警报PLAT934(如何删除衍射点)https://www.bilibili.com/video/BV1WJDJYbESq”“Olex2基操-OMIT指令的使用:https://www.bilibili.com/video/BV1av411e7f2”“Olex2OMIT指令的使用:https://www.bilibili.com/video/BV1bw411D7Nb”),最终结果如6所示,R1降为5.97%wR2降为16.65%
6改进后的最终结果
综上所述,显然该结构建模为[(THF)4Ca(Ind)2]·THF[(THF)4Ca(Ind)2]·0.5THF更加合理。
视频操作演示请参阅:
文献晶体数据改进示例26(THF占有率)https://www.bilibili.com/video/BV1W1KTz4EYR
如需论文PDF文档和CIF文件,请从以下链接下载:
提取码: 9jy6
参考文献
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声明:本文仅代表个人观点,笔者学识有限,资料整理过程中可能存在疏漏错误,请不吝指正。
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